If (f(x)=\sqrt{x+4}) and the domain is ([-4,12]), what is the range?यदि (f(x)=\sqrt{x+4}) और डोमेन ([-4,12]) है, तो रेंज क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([0,4])([0,4])
(\sqrt{x+4}) is an increasing function and gives (0) and (4) at the endpoints. In exams include endpoint values for a closed domain.(\sqrt{x+4}) बढ़ता हुआ फलन है और endpoints पर (0) तथा (4) देता है। परीक्षा में closed domain हो तो endpoint values शामिल करें।
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