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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\sqrt{x+12}-7)?

Answer and explanation

Correct answer: ([-7,\infty))

(\sqrt{x+12}\ge0), so (f(x)\ge-7). In exams an outside subtraction shifts the square-root range downward.

Related tags

Real-Valued-Functions Range Square-Root Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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