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What is the range of (f(x)=9-3|x+1|)?

Answer and explanation

Correct answer: ((-\infty,9])

Since (|x+1|\ge0), (9-3|x+1|\le9) and can go down without bound. In exams a negative coefficient changes the range direction.

Related tags

Real-Valued-FunctionsRangeModulus-FunctionReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematicsClass 11 Mcq

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