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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\frac{1}{|x+4|+3})?

Answer and explanation

Correct answer: ( (0,\frac{1}{3}])

The denominator (|x+4|+3) has minimum value (3) and can grow without bound. Hence the range is ( (0,\frac{1}{3}]).

Related tags

Real-Valued-Functions Range Modulus-Rational Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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