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What is the range of (f(x)=\frac{x^2+3}{x^2+7})?फलन (f(x)=\frac{x^2+3}{x^2+7}) की रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{3}{7},1))([\frac{3}{7},1))
(\frac{x^2+3}{x^2+7}=1-\frac{4}{x^2+7}). At (x=0), (\frac{3}{7}) is obtained and (1) is never obtained.(\frac{x^2+3}{x^2+7}=1-\frac{4}{x^2+7}) है। (x=0) पर (\frac{3}{7}) मिलता है और (1) कभी नहीं मिलता।
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