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If (f(x)=x^2-12) and the real domain is (\mathbb{R}), what is the range?यदि (f(x)=x^2-12) और वास्तविक डोमेन (\mathbb{R}) है, तो रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-12,\infty))([-12,\infty))
Since (x^2\ge0), (x^2-12\ge-12). In exams remember the minimum value of the square function is (0).क्योंकि (x^2\ge0), इसलिए (x^2-12\ge-12)। परीक्षा में square function की minimum value (0) याद रखें।
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