If \(f(x)=\sqrt{x^2-16}\), what is \(f(-5)\)?यदि \(f(x)=\sqrt{x^2-16}\), तो \(f(-5)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(3\)\(3\)
Substitute \(x=-5\): \(f(-5)=\sqrt{(-5)^2-16}=\sqrt{25-16}=\sqrt{9}=3\).\(x=-5\) रखने पर \(f(-5)=\sqrt{(-5)^2-16}=\sqrt{25-16}=\sqrt{9}=3\)।
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