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If \(f(x)=|x+6|\), what values can \(x\) have when \(f(x)=9\)?

Answer and explanation

Correct answer: \(x=3\) या \(x=-15\)

Substituting \(f(x)=9\) gives \(|x+6|=9\). A modulus equation has two cases: \(x+6=9\), which gives \(x=3\), and \(x+6=-9\), which gives \(x=-15\). Hence both values are possible. Option D considers only the positive branch and misses the negative one. Exam tip: for \(|A|=k\) with \(k>0\), always solve both \(A=k\) and \(A=-k\).

Related tags

Real-Valued-FunctionsModulusEquationsDomain-And-RangeReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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