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What is the range of (f(x)=\frac{x^2+2}{x^2+5})?फलन (f(x)=\frac{x^2+2}{x^2+5}) की रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{2}{5},1))([\frac{2}{5},1))
(\frac{x^2+2}{x^2+5}=1-\frac{3}{x^2+5}). At (x=0), the minimum (\frac{2}{5}) is attained and (1) is not attained.(\frac{x^2+2}{x^2+5}=1-\frac{3}{x^2+5}) है। (x=0) पर न्यूनतम (\frac{2}{5}) मिलता है और (1) नहीं मिलता।
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