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If (f(x)=\frac{1}{x+1}) and the domain is ([1,3]), what is the range?यदि (f(x)=\frac{1}{x+1}) और डोमेन ([1,3]) है, तो रेंज क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{1}{4},\frac{1}{2}])([\frac{1}{4},\frac{1}{2}])
On the positive interval, (\frac{1}{x+1}) decreases. At (x=1) and (x=3), values are (\frac{1}{2}) and (\frac{1}{4}).धनात्मक अंतराल पर (\frac{1}{x+1}) घटता है। (x=1) और (x=3) से (\frac{1}{2}) और (\frac{1}{4}) मिलते हैं।
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