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If the domain of the function \(f(x)=|x+2|\) is \([1,5]\), what is its range?

Answer and explanation

Correct answer: \([3,7]\)

For every \(x\in[1,5]\), \(x+2\) is positive, so \(f(x)=x+2\). This function increases on the domain: its minimum is \(f(1)=3\), and its maximum is \(f(5)=7\). Therefore, the range is \([3,7]\).

Related tags

Real-Valued-FunctionsDomain-And-RangeModulus-FunctionReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematicsClass 11 Mcq

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