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If \(f(x)=x^2\) and its domain is \([-6,-2]\), what is the range of the function?

Answer and explanation

Correct answer: \([4,36]\)

Every value in the domain \([-6,-2]\) is negative. For \(f(x)=x^2\), the endpoint values are \(f(-6)=36\) and \(f(-2)=4\). Since squaring takes all intermediate values on this interval, the range is \([4,36]\). Option B is incorrect because obtaining \(0\) would require \(x=0\), which is not in the domain. Exam tip: For a continuous function on a closed interval, check the endpoint values and any relevant extreme values to determine the range.

Related tags

Real-Valued-FunctionsDomain-And-RangeQuadratic-FunctionsIntervalsRelations-And-FunctionsReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And Functions

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