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What is the range of (f(x)=\frac{1}{x^2+9})?फलन (f(x)=\frac{1}{x^2+9}) की रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (0,\frac{1}{9}])( (0,\frac{1}{9}])
The denominator (x^2+9) has minimum value (9), so the maximum output is (\frac{1}{9}). (0) is only a limiting value, not an attained value.हर (x^2+9) की न्यूनतम वैल्यू (9) है, इसलिए अधिकतम आउटपुट (\frac{1}{9}) है। (0) केवल सीमा है, प्राप्त वैल्यू नहीं।
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