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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\sqrt{x+9}-4)?

Answer and explanation

Correct answer: ([-4,\infty))

(\sqrt{x+9}\ge0), so (\sqrt{x+9}-4\ge-4). In exams apply the vertical shift to the basic square-root range.

Related tags

Real-Valued-Functions Range Square-Root Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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