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What is the range of (f(x)=4|x-1|+2)?फलन (f(x)=4|x-1|+2) की रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([2,\infty))([2,\infty))
The minimum value of (|x-1|) is (0), so (f(x)\ge2). In exams the outside added (2) shifts the minimum upward.(|x-1|) की न्यूनतम वैल्यू (0) है, इसलिए (f(x)\ge2)। परीक्षा में बाहर जोड़ा गया (2) minimum को ऊपर करता है।
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