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What is the domain of (f(x)=\frac{1}{x^2-4x+5})?फलन (f(x)=\frac{1}{x^2-4x+5}) का डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R})(\mathbb{R})
The denominator (x^2-4x+5=(x-2)^2+1) is never (0). In exams complete the square to check the minimum denominator value.हर (x^2-4x+5=(x-2)^2+1) कभी (0) नहीं होता। परीक्षा में पूर्ण वर्ग बनाकर हर की न्यूनतम वैल्यू जांचें।
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