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What is the domain of (f(x)=\sqrt{\frac{x-2}{x+1}})?फलन (f(x)=\sqrt{\frac{x-2}{x+1}}) का डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((-\infty,-1)\cup[2,\infty))((-\infty,-1)\cup[2,\infty))
The expression inside the square root must satisfy (\frac{x-2}{x+1}\ge 0) and (x\ne -1). A sign table gives ((-\infty,-1)\cup[2,\infty)).वर्गमूल के अंदर (\frac{x-2}{x+1}\ge 0) और (x\ne -1) चाहिए। संकेत तालिका से ((-\infty,-1)\cup[2,\infty)) मिलता है।
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