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What is the range of (f(x)=\frac{x^2+1}{x^2+2})?फलन (f(x)=\frac{x^2+1}{x^2+2}) की रेंज क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{1}{2},1))([\frac{1}{2},1))
(\frac{x^2+1}{x^2+2}=1-\frac{1}{x^2+2}). The minimum (\frac{1}{2}) is obtained, but (1) is not obtained.(\frac{x^2+1}{x^2+2}=1-\frac{1}{x^2+2}) है। न्यूनतम (\frac{1}{2}) मिलता है, लेकिन (1) नहीं मिलता।
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