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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\sqrt{x^2+6x+13})?

Answer and explanation

Correct answer: ([2,\infty))

Inside, (x^2+6x+13=(x+3)^2+4), so the minimum is (4) and the range is ([2,\infty)). In exams complete the square inside first.

Related tags

Real-Valued-Functions Range Radical-Complete-Square Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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