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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\sqrt{4-x^2})?

Answer and explanation

Correct answer: ([0,2])

On the domain, (0\le 4-x^2\le 4), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.

Related tags

Real-Valued-Functions Range Semicircle-Function Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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