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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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What is the range of (f(x)=\frac{2}{x^2+4}+3)?

Answer and explanation

Correct answer: ( (3,\frac{7}{2}])

The range of (\frac{2}{x^2+4}) is ( (0,\frac{1}{2}]), so adding (3) gives ( (3,\frac{7}{2}]). In exams apply the vertical shift to the range.

Related tags

Real-Valued-Functions Range Rational-Shift Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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