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What is the range of (f(x)=|x-3|-2)?

Answer and explanation

Correct answer: ([-2,\infty))

Direct answer: A, [-2,∞). The modulus |x-3| is a distance, so it can never be negative. Its smallest value is 0, reached when x=3. Hence f(x)=|x-3|-2 has minimum 0-2=-2, and larger values continue without bound. Therefore the range is [-2,∞). Option A is correct because -2 is included: f(3)=-2. Option B [0,∞) forgets the subtraction of 2. Option C (-∞,-2] reverses the direction and incorrectly says values can decrease without limit. Option D all real numbers includes values below -2, which are impossible. Exam cue: for |x-a|+b, the range starts at b and goes upward when the coefficient is positive.

Related tags

Real-Valued-FunctionsRangeModulus-Function

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