What is the domain of (f(x)=\frac{1}{\sqrt{x^2-25}})?फलन (f(x)=\frac{1}{\sqrt{x^2-25}}) का डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((-\infty,-5)\cup(5,\infty))((-\infty,-5)\cup(5,\infty))
The square root is in the denominator, so (x^2-25>0) is required. In exams do not include equality for a denominator square root.हर में वर्गमूल है इसलिए (x^2-25>0) चाहिए। परीक्षा में हर वाले वर्गमूल के लिए बराबरी शामिल न करें।
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