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What is the domain of (f(x)=\sqrt{x^2-16})?फलन (f(x)=\sqrt{x^2-16}) का डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((-\infty,-4]\cup[4,\infty))((-\infty,-4]\cup[4,\infty))
The square root needs (x^2-16\ge 0), that is (x^2\ge 16). In exams (x^2\ge a^2) gives the outer intervals.वर्गमूल के लिए (x^2-16\ge 0), यानी (x^2\ge 16)। परीक्षा में (x^2\ge a^2) से बाहरी अंतराल मिलते हैं।
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