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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeEasy

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What is the range of (f(x)=\sqrt{9-x^2})?

Answer and explanation

Correct answer: ([0,3])

Since (0\le 9-x^2\le 9), we get (0\le \sqrt{9-x^2}\le 3). In exams first check the maximum and minimum values inside.

Related tags

Real-Valued-Functions Range Square-Root Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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