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What is the minimum value of (f(x)=(x-4)^2+6)?फलन (f(x)=(x-4)^2+6) की न्यूनतम वैल्यू क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6)(6)
Since ((x-4)^2\ge 0), the minimum value is (6). In exams set the squared part to (0) to get the minimum value.क्योंकि ((x-4)^2\ge 0), इसलिए न्यूनतम वैल्यू (6) है। परीक्षा में वर्ग वाला भाग (0) करके न्यूनतम वैल्यू पाएं।
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