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If \(f(x)=\sqrt{x}\), what is the value of \(f(16)\)?

Answer and explanation

Correct answer: 4

Substituting \(x=16\) in the given function gives \(f(16)=\sqrt{16}=4\). The principal square root is taken as the positive value, so the correct answer is 4. In such questions, first substitute the given input into the function and then simplify.

Related tags

Real-Valued-FunctionsFunction-ValueSquare-RootPrincipal-Square-RootReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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