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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeEasy

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What is the range of (f(x)=\sqrt{x-7}+2)?

Answer and explanation

Correct answer: ([2,\infty))

The minimum value of (\sqrt{x-7}) is (0), so (f(x)\ge 2). In exams the outside added (2) shifts the range upward.

Related tags

Real-Valued-Functions Range Square-Root Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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