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What is the range of (f(x)=\frac{1}{x^2+6})?फलन (f(x)=\frac{1}{x^2+6}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,\frac{1}{6}])((0,\frac{1}{6}])
The minimum denominator is (6), so the maximum value is (\frac{1}{6}). The value (0) is never reached but can be approached.हर का न्यूनतम मान (6) है, इसलिए अधिकतम मान (\frac{1}{6}) है। (0) कभी नहीं मिलता पर मान (0) के पास जा सकता है।
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