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What is the domain of (f(x)=\frac{5}{x^2-9})?फलन (f(x)=\frac{5}{x^2-9}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}-{-3,3})(\mathbb{R}-{-3,3})
The denominator must not be (0), and (x^2-9=0) gives (x=-3,3). Hence the domain is (\mathbb{R}-{-3,3}).हर (0) नहीं होना चाहिए और (x^2-9=0) पर (x=-3,3) मिलते हैं। इसलिए प्रांत (\mathbb{R}-{-3,3}) है।
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