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If \(f(x)=|x+1|-3\), what is the minimum value of \(f(x)\)?

Answer and explanation

Correct answer: -3

For every real \(x\), \(|x+1|\geq 0\). Its minimum value is \(0\), attained when \(x=-1\). Hence, the minimum value of \(f(x)=|x+1|-3\) is \(0-3=-3\). Exam tip: An absolute-value expression has minimum value \(0\) before any constant is added or subtracted.

Related tags

Modulus FunctionMinimum ValueReal Valued FunctionsRangeTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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