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If f(x) = 2√x for real x, what is its range?

Answer and explanation

Correct answer: [0, ∞)

For real x, the function is defined when x ≥ 0, and 2√x is always non-negative. It takes the value 0 at x = 0; moreover, for any y ≥ 0, choosing x = (y/2)² gives f(x) = y. Thus every non-negative value occurs, so the range is [0, ∞).

Related tags

RangeSquare-Root-FunctionDomain-And-RangeReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematicsClass 11 Mcq

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