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What is the domain of the function \(f(x)=\sqrt{2x-6}\)?

Answer and explanation

Correct answer: \([3,\infty)\)

For a real square root, the expression inside the radical must be non-negative. Thus, \(2x-6\geq 0\), which gives \(x\geq 3\). Therefore, the domain is \([3,\infty)\). Option B excludes \(3\), but \(f(3)=0\) is defined. Exam tip: For a real square-root function, always set the radicand to be \(\geq 0\).

Related tags

Relations And FunctionsDomain Of FunctionsSquare Root FunctionReal Valued FunctionsLinear InequalityTheir Domain And RangeReal Valued Functions Their Domain And RangeMathematics

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