What is the domain of the function \(f(x)=\sqrt{x+3}\)?

Correct answer: \([-3,\infty)\)

For a real square root, the expression under the radical must be zero or positive. Thus, \(x+3\ge 0\), which gives \(x\ge -3\). Therefore, the domain is \([-3,\infty)\). Option B reverses the inequality and includes values less than or equal to \(-3\), which do not make \(x+3\) non-negative except at the endpoint. Exam tip: For a square-root function, set the radicand greater than or equal to zero to find the domain.