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What is the real domain of \(f(x)=\sqrt{x-2}\)?\(f(x)=\sqrt{x-2}\) का वास्तविक domain क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \([2,\infty)\)\([2,\infty)\)
For \(\sqrt{x-2}\) to be real, we need the radicand to be non-negative: \(x-2\ge 0\). Solving gives \(x\ge 2\). Therefore the domain is \([2,\infty)\).\(\sqrt{x-2}\) को वास्तविक (real) होने के लिए radicand \(x-2\) का non-negative होना जरूरी है: \(x-2\ge 0\)। इससे \(x\ge 2\) मिलता है। इसलिए domain \([2,\infty)\) है।
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