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If the function \(f:\{1,2,3,4,5,6,7,8\}\to\{0,1\}\) is defined by \(f(n)=1\) when \(n\) is divisible by \(4\), and \(f(n)=0\) otherwise, what is \(f^{-1}(\{1\})\)?

Answer and explanation

Correct answer: \(\{4,8\}\)

The preimage \(f^{-1}(\{1\})\) consists of all elements of the domain whose image is \(1\). Among the domain elements, only \(4\) and \(8\) are divisible by \(4\), so \(f^{-1}(\{1\})=\{4,8\}\). Option D is incorrect because \(0\) is not in the domain. Exam tip: To find a preimage, select the inputs that map to the specified output value.

Related tags

PreimageDivisibilityFunctionsDomain And CodomainReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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