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If \(f:\{1,2,3,4,5,6\}\to\{0,1\}\) is defined by \(f(n)=0\) when \(n\) is divisible by \(3\), and \(f(n)=1\) otherwise, what is \(f^{-1}(\{0\})\)?

Answer and explanation

Correct answer: \(\{3,6\}\)

\(f^{-1}(\{0\})\) is the set of all elements in the domain whose image is \(0\). Among the given domain elements, only \(3\) and \(6\) are divisible by \(3\), so \(f^{-1}(\{0\})=\{3,6\}\). Option A contains the inputs that are not divisible by \(3\), while options C and D incorrectly mix codomain and domain elements. Exam tip: To find \(f^{-1}(\{a\})\), select every domain element whose function value is \(a\).

Related tags

PreimageDivisibilityFunctionsDomain And CodomainRelationsReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And Functions

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