If \(f=\{(x,y): y=\frac{x+1}{2},\ x\in\{1,3,5,7\}\}\), what is the range of \(f\)?

Correct answer: \(\{1,2,3,4\}\)

Substitute each domain value into \(y=\frac{x+1}{2}\): for \(x=1\), \(y=1\); for \(x=3\), \(y=2\); for \(x=5\), \(y=3\); and for \(x=7\), \(y=4\). Hence, the range is \(\{1,2,3,4\}\). Option B is the domain, not the range. Exam tip: to find a function’s range, list all distinct output values obtained from the given inputs.