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What happens at (x=2) in the graph of (y=\frac{x^2-4}{x-2})?ग्राफ (y=\frac{x^2-4}{x-2}) में (x=2) पर क्या होता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: A hole occursछिद्र बनता है
(\frac{x^2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}), but (x=2) remains excluded. So the graph is like (y=x+2) with a hole at (x=2).(\frac{x^2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}) है पर (x=2) निषिद्ध रहता है। इसलिए ग्राफ (y=x+2) जैसा है लेकिन (x=2) पर छिद्र है।
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