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Where does (y=\sin x) attain its maximum on (0\le x\le2\pi)?फलन (y=\sin x) का (0\le x\le2\pi) में अधिकतम मान कहाँ मिलता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=\frac{\pi}{2})(x=\frac{\pi}{2})
The maximum of (\sin x) is (1), attained at (x=\frac{\pi}{2}). Remember key points of standard trigonometric graphs.(\sin x) का अधिकतम मान (1) होता है, जो (x=\frac{\pi}{2}) पर मिलता है। मानक त्रिकोणमितीय ग्राफ के मुख्य बिंदु याद रखें।
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