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The graph of (f(x)=\sqrt{9-x^2}) is the upper part of which figure?फलन (f(x)=\sqrt{9-x^2}) का ग्राफ किस आकृति का ऊपरी भाग है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Circle (x^2+y^2=9)वृत्त (x^2+y^2=9)
From (y=\sqrt{9-x^2}), we get (x^2+y^2=9) with (y\ge0). The square root gives only the upper semicircle.(y=\sqrt{9-x^2}) से (y^2=9-x^2), इसलिए (x^2+y^2=9) और (y\ge0)। वर्गमूल के कारण केवल ऊपरी अर्धवृत्त मिलता है।
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