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Which is the horizontal asymptote of the graph (y=\frac{1}{x+2}-1)?ग्राफ (y=\frac{1}{x+2}-1) की क्षैतिज असिम्पटोट कौन-सी है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (y=-1)(y=-1)
For large (|x|), (\frac{1}{x+2}) approaches (0), so (y=-1). The outside constant shifts the horizontal asymptote.(\frac{1}{x+2}) बहुत बड़े (|x|) पर (0) के निकट जाता है, इसलिए (y=-1)। बाहरी स्थिरांक क्षैतिज असिम्पटोट बदलता है।
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