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What is the minimum value of the graph (y=(x+1)^2-4)?ग्राफ (y=(x+1)^2-4) का न्यूनतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( -4 )( -4 )
The minimum of ((x+1)^2) is (0), hence (y_{\min}=-4). A completed square often gives the minimum directly.((x+1)^2) का न्यूनतम मान (0) है, इसलिए (y_{\min}=-4) है। पूर्ण वर्ग देखकर न्यूनतम मान तुरंत मिल सकता है।
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