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Which function is symmetric about the y-axis and has a minimum value of 2?

Answer and explanation

Correct answer: \(y=x^2+2\)

For \(y=x^2+2\), \(f(-x)=(-x)^2+2=x^2+2=f(x)\), so it is an even function and its graph is symmetric about the y-axis. Since \(x^2\geq 0\), we have \(y=x^2+2\geq 2\); hence the minimum value is 2, attained at \(x=0\). Option C has minimum value 0 and is symmetric about \(x=2\), not the y-axis. Exam tip: test y-axis symmetry using \(f(-x)=f(x)\).

Related tags

GraphsSymmetryEven FunctionsMinimum ValueStandard FunctionsGraphs Of Standard FunctionsRelations And FunctionsMathematics

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