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What are the vertical asymptotes of the graph of (f(x)=\frac{1}{x^2-9})?फलन (f(x)=\frac{1}{x^2-9}) के ग्राफ के लंबवत आसमापी कौन-से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=-3) and (x=3)(x=-3) और (x=3)
The denominator (x^2-9=(x-3)(x+3)) is zero at (x=\pm3). In exams, find vertical asymptotes from the zeroes of the denominator.हर (x^2-9=(x-3)(x+3)) शून्य होने पर (x=\pm3) मिलता है। परीक्षा में हर के शून्यों से लंबवत आसमापी खोजें।
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