0 reads0 ratings0 helpful
The graph (y=\sqrt{9-x^2}) is the upper part of which geometric figure?ग्राफ (y=\sqrt{9-x^2}) किस ज्यामितीय आकृति का ऊपरी भाग है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: circle with centre ((0,0)) and radius (3)केंद्र ((0,0)) और त्रिज्या (3) वाला वृत्त
Squaring gives (x^2+y^2=9) with (y\ge0). In exams, identify (\sqrt{r^2-x^2}) as the upper semicircle.वर्ग करने पर (x^2+y^2=9) और (y\ge0) मिलता है। परीक्षा में (\sqrt{r^2-x^2}) को ऊपरी अर्धवृत्त पहचानें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
