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Which function gives a graph symmetric about the y-axis?

Answer and explanation

Correct answer: f(x) = x^2

The governing concept is an even function. A graph is symmetric about the y-axis exactly when f(-x) = f(x) for every x in its domain. For f(x) = x^2, f(-x) = (-x)^2 = x^2 = f(x), so the parabola has mirror symmetry about the y-axis. Therefore option B is correct. In contrast, f(x) = x^3 is odd because f(-x) = -f(x), giving symmetry about the origin rather than the y-axis. The function x + 1 is neither even nor odd. The real function √x has domain x ≥ 0 only, so reflecting its graph across the y-axis would require points with negative x that are not in its domain.

Related tags

Even-FunctionsSymmetryStandard-GraphsGraphs Of Standard FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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