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At which points do the graphs of f(x) = x^2 and g(x) = √x meet?

Answer and explanation

Correct answer: (0, 0) and (1, 1)

The governing concept is that an intersection point must satisfy both function equations and all domain restrictions. Set x^2 = √x. Since √x is real only for x ≥ 0, restrict the search to nonnegative x. Squaring is then valid and gives x^4 = x, or x(x^3 - 1) = 0. Hence x = 0 or x = 1. Substituting into either function gives y = 0 and y = 1 respectively, so the intersections are (0, 0) and (1, 1). Therefore option C is correct. The point (-1, 1) is invalid because √(-1) is not real. Options A and B each omit one of the two valid solutions.

Related tags

Graph-IntersectionsDomainRadical-FunctionsGraphs Of Standard FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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