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Why is the graph of (f(x)=x^3) symmetric about the origin?

Answer and explanation

Correct answer: because (f(-x)=-f(x))

The direct answer is option B. A graph is symmetric about the origin when every point (x,y) is matched by the point (-x,-y). For f(x)=x^3, calculate f(-x)=(-x)^3=-x^3=-f(x). This is the definition of an odd function, and the graph of an odd function has origin symmetry. Option B states exactly this relation. Option A, f(-x)=f(x), defines an even function, whose graph is symmetric about the y-axis, not generally the origin. Option C, f(x)≥0, is false for negative x because x^3 is negative; it also does not state a symmetry rule. Option D, f(x)≤0, is false for positive x and likewise cannot establish origin symmetry. For example, (1,1) lies on the graph and its origin-reflected point (-1,-1) also lies on it. Remember: even means y-axis symmetry, odd means origin symmetry. The supplied answer is correct.

Related tags

Relations-FunctionsGraphsCubic-Function

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