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Which equation fails the vertical line test?

Answer and explanation

Correct answer: \(y^2=x+1\)

The equation \(y^2=x+1\) can be rewritten as \(y=\pm\sqrt{x+1}\). Thus, for every \(x>-1\), there are two corresponding values of \(y\), so a vertical line can intersect the graph at two points. Therefore, it fails the vertical line test. In options B, C, and D, each allowed \(x\)-value gives exactly one \(y\)-value. Exam tip: a relation represents a function of \(x\) only if every vertical line intersects its graph at most once.

Related tags

Relations And FunctionsVertical Line TestGraphs Of FunctionsStandard FunctionsGraphs Of Standard FunctionsMathematicsClass 11 Mcq

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